Question 5:
ABC is an isosceles triangle with AB = AC. Drawn AP ⊥ BC to show that ∠B = ∠C.
Answer:
In ∆APB and ∆APC,
∠APB = ∠APC (Each 90º)
AB =AC (Given)
AP = AP (Common)
∆APB ≅ ∆APC (Using RHS congruence rule)
∠B = ∠C (By using CPCT)
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