Question 1:
ABC is a triangle. Locate a point in the interior of ∆ABC which is equidistant from all
the vertices of ∆ABC.
Answer:
Circumcentre of a triangle is always equidistant from all the vertices of that triangle.
Circumcentre is the point where perpendicular bisectors of all the sides of the
triangle meet together.
In ∆ABC, we can find the circumcentre by drawing the perpendicular bisectors of
sides AB, BC, and CA of this triangle. O is the point where these bisectors are
meeting together. Therefore, O is the point which is equidistant from all the vertices
of ∆ABC.
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