Question 5:
You have studied in Class IX that a median of a triangle divides it into two triangles of equal areas. Verify this result for MABC whose vertices are A (4, − 6), B (3, − 2) and C (5, 2)
Answer:
Let the vertices of the triangle be A (4, −6), B (3, −2), and C (5, 2).
Let D be the mid-point of side BC of ΔABC. Therefore, AD is the median in ΔABC.
However, area cannot be negative. Therefore, area of ΔADC is 3 square units.
Clearly, median AD has divided ΔABC in two triangles of equal areas.
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