Question 3:

If sin A = 3/4, calculate cos A and tan A.

Answer:

Let ΔABC be a right-angled triangle, right-angled at point B.

Given that,

sin A= 3/4

BC/AC = 3/4

Let BC be 3k. Therefore, AC will be 4k, where k is a positive integer.

Applying Pythagoras theorem in ΔABC, we obtain

AC² = AB² + BC²

(4k)² = AB² + (3k)²

16k ² − 9k ² = AB²

7k ² = AB²

AB = √7 k

 

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