Question 5:
Given sec θ = 13/12, calculate all other trigonometric ratios.
Answer:
Consider a right-angle triangle ΔABC, right-angled at point B.
If AC is 13k, AB will be 12k, where k is a positive integer.
Applying Pythagoras theorem in ΔABC, we obtain
(AC)2 = (AB)2 + (BC)2
(13k)2 = (12k)2 + (BC)2
169k2 = 144k2 + BC2
25k2 = BC2
BC = 5k
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