Question 7:

If cot θ = 7/8, evaluate

Answer:

Let us consider a right triangle ABC, right-angled at point B.

 

If BC is 7k, then AB will be 8k, where k is a positive integer.

Applying Pythagoras theorem in ΔABC, we obtain

AC² = AB² + BC²

= (8k)² + (7k)²

= 64k² + 49k²

= 113k²

AC = √113 k

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