Question 4:
A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:
(i) Minor segment (ii) Major sector [Use π = 3.14]
Answer:
Let AB be the chord of the circle subtending 90° angle at centre O of the circle.
Area of major sector OADB
Area of minor segment ACB = Area of minor sector OACB − Area of ΔOAB = 78.5 − 50 = 28.5 cm2
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