Question 13:
In the given figure, a square OABC is inscribed in a quadrant OPBQ. If OA = 20 cm, find the area of the shaded region. [Use π = 3.14]
Answer:
In ΔOAB,
OB2 = OA2 + AB2
= (20)2 + (20)2
OB = 20√2
Radius (r) of circle = 20√2 cm
Area of OABC = (Side)2 = (20)2 = 400 cm2
Area of shaded region = Area of quadrant OPBQ − Area of OABC
= (628 − 400) cm2
= 228 cm2
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