NCERT Solution Class XI Mathematics Sets Question 4 (Ex 1.6)

Question 4:

If S and T are two sets such that S has 21 elements, T has 32 elements, and S ∩ T has 11 elements, how many elements does S ∪ T have?

Answer

It is given that:

n(S) = 21, n(T) = 32, n(S ∩ T) = 11
We know that:

n (S ∪ T) = n (S) + n (T) − n (S ∩ T)

∴ n (S ∪ T) = 21 + 32 − 11 = 42
Thus, the set (S ∪ T) has 42 elements.

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