Question 9:
Answer
The equation can also the written as √2x2 + √2x + 1 = 0
On comparing this equation with ax2 + bx + c = 0, we obtain
a = √2, b = √2, and c = 1
∴ Discriminant (D) = b2 – 4ac = (√2)2 – 4 × (√2) × 1 = 2 – 4√2
Therefore, the required solutions are
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