Question 6:
Show that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
Answer:
In ∆PNM,
∠N = 90º
∠P + ∠N + ∠M = 180º (Angle sum property of a triangle)
∠P + ∠M = 90º
Clearly, ∠M is an acute angle.
∠M < ∠N
PN < PM (Side opposite to the smaller angle is smaller)
Similarly, by drawing different line segments from P to l, it can be proved that PN is
smaller in comparison to them.
Therefore, it can be observed that of all line segments drawn from a given point not
on it, the perpendicular line segment is the shortest.
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