Question 8:
Show that the angles of an equilateral triangle are 60º each.
Answer:
Let us consider that ABC is an equilateral triangle.
Therefore, AB = BC = AC
AB = AC
∠C = ∠B (Angles opposite to equal sides of a triangle are equal)
Also,
AC = BC
∠B = ∠A (Angles opposite to equal sides of a triangle are equal)
Therefore, we obtain
∠A = ∠B = ∠C
In ∆ABC,
∠A + ∠B + ∠C = 180°
∠A + ∠A + ∠A = 180°
3∠A = 180°
∠A = 60°
∠A = ∠B = ∠C = 60°
Hence, in an equilateral triangle, all interior angles are of measure 60º.
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