Question 3:
What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1024 kg and radius of the earth is 6.4 × 106 m).
Answer:
According to the universal law of gravitation, gravitational force exerted on an object of mass m is given by:
Where,
Mass of Earth, M = 6 × 1024 kg
Mass of object, m = 1 kg
Universal gravitational constant, G = 6.7 × 10−11 Nm2 kg−2
Since the object is on the surface of the Earth, r = radius of the Earth (R)
r = R = 6.4 × 106 m
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