Question 1:

Find the area of the shaded region in the given figure, if PQ = 24 cm, PR = 7 cm and O is the centre of the circle. [Use π = 22/7]

Answer:

It can be observed that RQ is the diameter of the circle. Therefore, ∠RPQ will be 90º.

By applying Pythagoras theorem in ΔPQR,

RP² + PQ² = RQ²

(7)² + (24)² = RQ²

RQ = √625 = 25

Radius of circle, OR = RQ/2 = 25/2

Since RQ is the diameter of the circle, it divides the circle in two equal parts.

Area of shaded region = Area of semi-circle RPQOR − Area of ΔPQR

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