Question 7:
A chord of a circle of radius 12 cm subtends an angle of 120° at the centre. Find the area of the corresponding segment of the circle. [Use π = 3.14 and √3 = 1.73]
Answer:
Let us draw a perpendicular OV on chord ST. It will bisect the chord ST.
SV = VT
In ΔOVS,
Area of segment SUT = Area of sector OSUT − Area of ΔOST
= 150.72 − 62.28 = 88.44 cm2
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