Question 8:

Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively.

Answer:

Given that,

a₂ = 14

a₃ = 18

d = a₃ − a₂ = 18 − 14 = 4

a₂ = a + d

14 = a + 4

a = 10

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