Question 3:
If tan 2A = cot (A− 18°), where 2A is an acute angle, find the value of A.
Answer:
Given that,
tan 2A = cot (A− 18°)
cot (90° − 2A) = cot (A −18°)
90° − 2A = A− 18°
108° = 3A
A = 36°
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Question 3:
If tan 2A = cot (A− 18°), where 2A is an acute angle, find the value of A.
Answer:
Given that,
tan 2A = cot (A− 18°)
cot (90° − 2A) = cot (A −18°)
90° − 2A = A− 18°
108° = 3A
A = 36°
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