Question 9:
(i) sin A cos C + cos A sin C
(ii) cos A cos C − sin A sin C
Answer:
tan A = 1/√3
BC/AB = 1/√3
If BC is k, then AB will be √3 k , where k is a positive integer.
In ΔABC,
AC2 = AB2 + BC2
= (√3 k)2 + (k)2
= 3k2 + k2 = 4k2
∴ AC = 2k
(i) sin A cos C + cos A sin C
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