Question 1:
Solve the following pairs of equations by reducing them to a pair of linear equations:
Answer:
Multiplying equation (1) by 3, we obtain
6p + 9q = 6 (3)
Adding equation (2) and (3), we obtain
By cross-multiplication, we obtain
Putting this value in equation (1), we obtain
(v)
By cross-multiplication method, we obtain
By cross-multiplication method, we obtain
Substituting in equation (3), we obtain
y = 2
Hence, x = 3, y = 2
Substituting in (2), we obtain
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