NCERT Solution Class X Mathematics Polynomials Question 2 (Ex 2.2)

Question 2:

Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively.

(i)   1/4, –1           (ii) √2, 1/3          (iii) 0, √5

(iv)  1,1               (v) –1/4, ¼           (vi) 4, 1

Answer:

(i)   1/4, –1

Let the polynomial be ax2 + bx + c, and its zeroes be  α and β.

 

If a = 4, then b = -1, c = -4

Therefore, the quadratic polynomial is 4x2 − x − 4.

(ii) √2, 1/3

Let the polynomial be ax2 + bx + c, and its zeroes be  α and β.

Therefore, the quadratic polynomial is 3x2 − 3√2x + 1.

 (iii) 0, √5

Let the polynomial be ax2 + bx + c, and its zeroes be  α and β.

Therefore, the quadratic polynomial is x2 + √5.

(iv)  1,1

Let the polynomial be ax2 + bx + c, and its zeroes be  α and β.

Therefore, the quadratic polynomial is x2 – x + 1.

(v) –1/4, ¼

Let the polynomial be ax2 + bx + c, and its zeroes be  α and β.

Therefore, the quadratic polynomial is 4x2 + x + 1.

(vi) 4 , 1

Let the polynomial be ax2 + bx + c.

Therefore, the quadratic polynomial is x2 – 4x + 1.

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