Question 4:
ABC is an isosceles triangle right angled at C. prove that AB2 = 2 AC2.
Answer:
Given that ∆ABC is an isosceles triangle
∴ AC = CB
Applying Pythagoras theorem in ∆ABC (i.e., right-angled at point C), we obtain
AC2 + CB2 = AB2
⇒ AC2 + AC2 = AB2 (AC = CB)
⇒ 2AC2 = AB2
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