Question 5:
S and T are point on sides PR and QR of ;PQR such that ∠P = ∠RTS. Show that ∆RPQ ∼ ∆RTS.
Answer:
In ∆RPQ and ∆RST,
∠RTS = ∠QPS (Given)
∠R = ∠R (Common angle)
∴ ∆RPQ ∼ ∆RTS (By AA similarity criterion)
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