Question 6:
In the following figure, if ∆ABE ≅ ∆ACD, show that ∆ADE ∼ ∆ABC.
Answer:
It is given that ∆ABE ≅ ∆ACD.
∴ AB = AC [By CPCT] (1)
And, AD = AE [By CPCT] (2)
In ∆ADE and ∆ABC,
AD/AB = AE/AC [Dividing equation (2) by (1)]
∠A = ∠A [Common angle]
∴ ∆ADE ∼ ∆ABC [By SAS similarity criterion]
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