Question 9:
A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladderfrom base of the wall.
Answer:
Let OA be the wall and AB be the ladder.
Therefore, by Pythagoras theorem,
AB2 = OA2 + BO2
(10 m)2 = (8 m)2 + OB2
100 m2 = 64 m2 + OB2
OB2 = 36 m2
OB = 6 m
Therefore, the distance of the foot of the ladder from the base of the wall is 6 m.
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