Question 13:
Answer
Let z = r cos θ + ir sin θ
i.e., r cos θ = −1/2 and r sin θ = 1/2
On squaring and adding, we obtain
Therefore, the modulus and argument of the given complex number are 1/√2 and 3π/4 respectively.
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Question 13:
Answer
Let z = r cos θ + ir sin θ
i.e., r cos θ = −1/2 and r sin θ = 1/2
On squaring and adding, we obtain
Therefore, the modulus and argument of the given complex number are 1/√2 and 3π/4 respectively.
Latest Govt Job & Exam Updates: