LOYOLA COLLEGE (AUTONOMOUS), CHENNAI – 600 034
M.Sc. DEGREE EXAMINATION – STATISTICS
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FOURTH SEMESTER – APRIL 2006
ST 4951 – ADVANCED OPERATIONS RESEARCH
Date & Time : 27-04-2006/9.00-12.00 Dept. No. Max. : 100 Marks
SECTION A
Answer ALL questions. (10 ´ 2 =20 marks)
- Define linearly independent vectors.
- Define a Mixed Integer Programming Problem.
- What is the need for Integer Programming Problems?
- State Bellman’s principle of optimality.
- What is meant by Separable Programming Problem?
- Define Goal Programming Problem.
- Write down the mathematical formulation of a Geometric Programming Problem.
- Explain the stage and state variables in a dynamic Programming Problem.
- Name the methods used in solving a Quadratic Programming Problem.
- What is the need for Dynamic Programming Problem?
SECTION B
Answer any FIVE questions. (5 ´ 8 =40 marks)
- Explain the construction of fractional cut in the Gomory’s constraint method.
- State all the characteristics of a Dynamic Programming Problem.
- In the network given below are different routes for reaching city B from city A passing through a number of other cities, the lengths of the individual routes are shown on the arrows. It is required to determine the shortest route from A to B. Formulate the problem as a Dynamic Programming Problem model, explicitly defining the stages, states and then find the optimal solution.
6
5 3 2 4
7 4 2 2
5
- Solve the following Non-Linear Programming Problem:
Optimize Z = X 2 +Y 2 + W 2,
subject to X +Y + W = 1,
X, Y, W ≥ 0.
- Derive the Kuhn-Tucker necessary conditions for solving a Generalized Non-Linear Programming Problem with one inequality constraint.
- Derive the orthogonality and Normality conditions for solving the unconstrained Geometric Programming Problem.
- Convert the following Stochastic Programming Problem into an equivalent deterministic model, max Z = X1 + 2 X2 + 5 X3 ,subject to
P [a1 X1 + 3 X2 + a3 X3 ≤ 10 ] ≥ 0.9,
P [ 7 X1 + 5 X2 + X3 ≤ b2 ] ≥ 0.1,
X1, X2, X3 ≥ 0.
Assume that a1, a3 are independent normally distributed random variables with means E (a1) = 2, E (a3) = 5, V (a1) = 9, V (a3) = 16. Also assume that
b2 ~ N (15, 25).
- The manufacturing plant of an electronics firm produces two types of T.V. sets, both colour and black-and-white. According to past experiences, production of either a colour or a black-and-white set requires an average of one hour in the plant. The plant has a normal production capacity of 40 hours a week. The marketing department reports that, because of limited sales opportunity, the maximum number of colour and black-and-white sets that can be sold are 24 and 30 respectively for the week. The gross margin from the sale of a colour set is Rs. 80, whereas it is Rs. 40 from a black-and-white set.
The chairman of the company has set the following goals as arranged in the order of their importance to the organization.
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- Avoid any underutilization of normal production capacity (on layoffs of production workers).
- Sell as many T.V. sets as possible. Since the gross margin from the sale of colour T.V. set is twice the amount from a black-and-white set, he has twice as much desire to achieve sales for colour sets as black-and-white sets.
- The chairman wants to minimize the overtime operation of the plant as much as possible.
Formulate this as a Goal Programming Problem.
SECTION C
Answer any TWO questions. (2 x 20 =40 marks)
- Solve the following Integer Programming Problem:
Max Z = 3 X1 + X2 + 3 X3
subject to – X1 + 2 X2 + X3 ≤ 4,
4 X2 – 3 X3 ≤ 2,
X1 – 3 X2 + 2 X3 ≤ 3,
X1, X2, X3 ≥ 0.
- (i) Solve the following Dynamic Programming Problem (DPP):
Min Z = subject to = C , x j ≥ 0 , j = 1,2, … n. C > 0.
(ii) Solve the following LPP by DPP technique:
Max Z = 3 X1 + 4 X2 ,
subject to 2 X1 + X2 ≤ 40,
2 X1 + 5 X2 ≤ 180,
X1, X2 ≥ 0.
- Use Kuhn-Tucker necessary conditions to solve the following Generalized Non- Linear Programming Problem:
Max Z = 2 X1 – X12 + X2
subject to 2 X1 + 3 X2 ≤ 6,
2 X1 + X2 ≤ 4,
X1, X2 ≥ 0.
- Solve the following Quadratic Programming Problem using Wolfe’s algorithm:
Max Z = 4 X1 + 6 X2 – 2 X12 – 2 X1 X2 – 2 X22 ,
subject to X1 + 2 X2 ≤ 2,
X1, X2 ≥ 0.
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