JEE Advanced Exam 2008 Paper-II Chemistry Question Paper With Answer Key

Chemistry

SECTION – I

Straight Objective Type

This section contains 9 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D), out of which ONLY ONE is correct.

1. The correct stability order for the following species is

(A)  (II) > (IV) > (I) > (III)

(B)  (I) > (II) > (III) > (IV)

(C)  (II) > (I) > (IV) > (III)

(D)  (I) > (III) > (II) > (IV)

Answer: (D)

2. Cellulose upon acetylation with excess acetic anhydride/H2SO4 (catalytic) gives cellulose triacetate whose structure is

(A) 

(B) 

(C) 

(D) 

Answer: (A)

3. In the following reaction sequence, the correct structures of E, F and G are

(A) 

(B) 

(C) 

(D) 

Answer: (C)

4. Among the following the coloured compound is

(A)  CuCl

(B)  K3[Cu(CN)4]

(C)  CuF2

(D)  [Cu(CH3CN)4]BF4

Answer: (C)

5. Both [Ni(CO)4] and [Ni(CN)4]2− are diamagnetic. The hybridization of nickel in these complexes, respectively, are

(A)  sp3, sp3

(B)  sp3, dsp2

(C)  dsp2, sp3

(D)  dsp2, dsp2

Answer: (B)

6. The IUPAC name of [Ni(NH3)4][NiCl4] is

(A)  Tetrachloronickel (II) – tetraamminenickel (II)

(B)  Tetraamminenickel (II) – tetrachloronickel (II)

(C)  Tetraamminenickel (II) – tetrachloronickelate (II)

(D)  Tetrachloronickel (II) – tetraamminenickelate (0)

Answer: (C)

7. Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of H2 gas at the cathode is (1 Faraday = 96500 C mol−1)

(A)  9.65 × 104 sec

(B)  19.3 × 104 sec

(C)  28.95 × 104 sec

(D)  38.6 × 104 sec

Answer: (B)

8. Among the following, the surfactant that will form micelles in aqueous solution at the lowest molar concentration at ambient conditions is

(A)  CH3(CH2)15N+(CH3)3Br

(B) 

(C)  CH3(CH2)6COONa+

(D)  CH3(CH2)11N+(CH3)3Br

Answer: (A)

9. Solubility product constant (Ksp) of salts of types MX, MX2 and M3X at temperature ‘T’ are 4.0 × 10−8, 3.2 × 10−14 and 2.7 × 10−15, respectively. Solubilities (mole dm−3) of the salts at temperature ‘T’ are in the order

(A)  MX > MX2 > M3X

(B)  M3X > MX2 > MX

(C)  MX2 > M3X > MX

(D)  MX > M3X > MX2

Answer: (D)

SECTION – II

Reasoning Type

This section contains 4 reasoning type questions. Each question has 4 choices (A), (B), (C) and (D), out of which ONLY ONE is correct.

10. STATEMENT-1: Aniline on reaction with NaNO2/HCl at 0℃ followed by coupling with β-naphthol gives a dark blue coloured precipitate.

and

STATEMENT-2: The colour of the compound formed in the reaction of aniline with NaNO2/HCl at 0℃ followed by coupling with β-naphthol is due to the extended conjugation.

(A)  STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is correct explanation for STATEMENT-1

(B)  STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

(C)  STATEMENT-1 is True, STATEMENT-2 is False

(D)  STATEMENT-1 is False, STATEMENT-2 is True

Answer: (D)

11. STATEMENT-1: [Fe(H2O)5NO]SO4 is paramagnetic.

and

STATEMENT-2: The Fe in [Fe(H2O)5NO]SO4 has three unpaired electrons.

(A)  STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is correct explanation for STATEMENT-1

(B)  STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

(C)  STATEMENT-1 is True, STATEMENT-2 is False

(D)  STATEMENT-1 is False, STATEMENT-2 is True

Answer: (A)

12. STATEMENT-1: The geometrical isomers of the complex [M(NH3)4Cl2] are optically inactive.

and

STATEMENT-2: Both geometrical isomers of the complex [M(NH3)4Cl2] possess axis of symmetry.

(A)  STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is correct explanation for STATEMENT-1

(B)  STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

(C)  STATEMENT-1 is True, STATEMENT-2 is False

(D)  STATEMENT-1 is False, STATEMENT-2 is True

Answer: (B)

13. STATEMENT-1: There is a natural asymmetry between converting work to heat and converting heat to work.

and

STATEMENT-2: No process is possible in which the sole result is the absorption of heat from a reservoir and its complete conversion into work.

(A)  STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is correct explanation for STATEMENT-1

(B)  STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

(C)  STATEMENT-1 is True, STATEMENT-2 is False

(D)  STATEMENT-1 is False, STATEMENT-2 is True

Answer: (A)

SECTION – III

Linked Comprehension Type

This section contains 2 paragraphs. Based upon each paragraph, 3 multiple choice questions have to be answered. Each question has 4 choices (A), (B), (C) and (D), out of which ONLY ONE is correct.

Paragraph for Question Nos. 14 to 16

A tertiary alcohol H upon acid catalysed dehydration gives a product I. Ozonolysis of I leads to compounds J and K. Compound J upon reaction with KOH gives benzyl alcohol and a compound L, whereas K on reaction with KOH gives only M,

14. Compound H is formed by the reaction of

(A) 

(B) 

(C) 

(D) 

Answer: (B)

15. The structure of compound I is

(A) 

(B) 

(C) 

(D) 

Answer: (A)

16. The structures of compounds J, K and L, respectively, are

(A)  PhCOCH3, PhCH2COCH3 and PhCH2COOK+

(B)  PhCHO, PhCH2CHO and PhCOOK+

(C)  PhCOCH3, PhCH2CHO and CH3COOK+

(D)  PhCHO, PhCOCH3 and PhCOOK+

Answer: (D)

Paragraph for Question Nos. 17 to 19

In hexagonal systems of crystals, a frequently encountered arrangement of atoms is described as a hexagonal prism. Here, the top and bottom of the cell are regular hexagons and three atoms are sandwiched in between them. A space-filling model of this structure, called hexagonal close-packed (HCP), is constituted of a sphere on a flat surface surrounded in the same plane by six identical spheres as closely as possible. Three spheres are then placed over the first layer so that they touch each other and represent the second layer. Each one of these three spheres touches three spheres of the bottom layer. Finally, the second layer is covered with a third layer that is identical to the bottom layer in relative position. Assumer radius of every sphere to be ‘r’.

17. The number of atoms on this HCP unit cell is

(A)  4

(B)  6

(C)  12

(D)  17

Answer: (B)

18. The volume of this HCP unit cell is

(A) 

(B) 

(C) 

(D) 

Answer: (A)

19. The empty space in this HCP unit cell is

(A)  74%

(B)  47.6%

(C)  32%

(D)  26%

Answer: (D)

SECTION – IV

Matrix-Match Type

This contains 3 questions. Each question contains statements given in two columns which have to be matched. Statements (A, B, C, D) in column I have to be matched with statements (p, q, r, s) in column II.

20. Match the compounds in Column I with their characteristic test(s)/ reaction(s) given in Column II.

(A)  A – r, s ; B – p, q ; C – p, q, r ; D – p, s

(B)  A – q, p ; B – s, r ; C – s, p, r ; D – q, p

(C)  A – p, r ; B – r, s ; C – s, q, r ; D – r, p

(D)  A – s, r ; B – r, p ; C – s, r, q ; D – s, r

Answer: (A)

21. Match the entries in Column I with the correctly related quantum number(s) in Column II.

(A)  A – s, r ; B – r, p ; C – s, r, q ; D – s, r

(B)  A – p, r ; B – r, s ; C – s, q, r ; D – r, p

(C)  A – r, s ; B – p, q ; C – p, q, r ; D – p, s

(D)  A –q ; B – s ; C – p, q, r ; D – p, q, r

Answer: (D)

22. Match the conversions in Column I with the type(s) of reaction(s) given in Column II.

(A)  A – p ; B – q ; C – p, r ; D – p, s

(B)  A – q ; B – r ; C – s, q ; D – r, p

(C)  A – s ; B – p ; C – r, q ; D – p, r

(D)  A – r ; B – s ; C – q, p ; D – s, r

Answer: (A)

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