JEE Advanced Exam 2009 Paper-I Chemistry Question Paper With Answer Key

Part I : Chemistry

Section-I

Single Correct Choice Type

This section contains 8 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for its answer, out which ONLY ONE is correct.

1. Given that the abundances of isotopes 54Fe, 56Fe and 57Fe are 5%, 90% and 5% respectively, the atomic mass of Fe is

(A)   55.85

(B)   55.95

(C)   55.75

(D)   56.05

Answer: (B)

2. The term that corrects for the attractive forces present in a real gas in the van der Waals equation is

(A)   nb

(B)    

(C)     

(D)   −nb

Answer: (B)

3. Among the electrolytes Na2SO4, CaCl2, Al2(SO4)3 and NH4Cl, the most effective coagulating agent for Sb2S3 sol is

(A)   Na2SO4

(B)   CaCl2

(C)   Al2(SO4)3

(D)   NH4Cl

Answer: (C)

4. The Henry’s law constant for the solubility of N2 gas in water at 298 K is 1.0 × 105 The mole fraction of N2 in air is 0.8. The number of moles of N2 from air dissolved in 10 moles of water at 298 K and 5 atm pressure is

(A)   4.0 × 10−4

(B)   4.0 × 10−5

(C)   5.0 × 10−4

(D)   4.0 × 10−6

Answer: (A)

5. The reaction of P4 with X leads selectively to P4O6. The X is

(A)   Dry O2

(B)   A mixture of O2 and N2

(C)   Moist O2

(D)   O2 in the presence of aqueous NaOH

Answer: (B)

6. The correct acidity order of the following is

(A)   (III) > (IV) > (II) > (I)

(B)   (IV) > (III) > (I) > (II)

(C)   (III) > (II) > (I) > (IV)

(D)   (II) > (III) > (IV) > (I)

Answer: (A)

7. Among cellulose, poly(vinyl chloride), nylon and natural rubber, the polymer in which the intermolecular force of attraction is weakest is

(A)   Nylon

(B)   Poly(vinyl chloride)

(C)   Cellulose

(D)   Natural Rubber

Answer: (D)

8. The IUPAC name of the following compound is

(A)   4-Bromo-3-cyanophenol

(B)   2-Bromo-5-hydroxybenzonitrile

(C)   2-Cyano-4-hydroxybromobenzene

(D)   6-Bromo-3-hdyroxybenzonitrile

Answer: (B)

SECTION-II

Multiple Correct Choice Type

This section contains 4 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for its answer, out which ONE OR MORE is/are correct.

9. The correct statement(s) regarding defects in solids is(are)

(A)   Frenkel defect is usually favoured by a very small difference in the sizes of cation and anion

(B)   Frenkel defect is a dislocation defect

(C)   Trapping of an electron in the lattice leads to the formation of F-center

(D)   Schottky defects have no effect on the physical properties of solids

Answer: (B, C)

10. The compound(s) that exhibit(s) geometrical isomerism is(are)

(A)   [Pt(en)Cl2]

(B)   [Pt(en)2]Cl2

(C)   [Pt(en)2Cl2]Cl2

(D)   [Pt(NH3)2Cl2]

Answer: (C, D)

11. The compound(s) formed upon combustion of sodium metal in excess air is(are)

(A)   Na2O2

(B)   Na2O

(C)   NaO2

(D)   NaOH

Answer: (A, B)

12. The correct statement(s) about the compound H3C(HO)HC−CH=CH−CH(OH)CH3 (X) is(are)

(A)   The total number of stereoisomers possible for X is 6

(B)   The total number of diastereomers possible for X is 3

(C)   If the stereochemistry about the double bond in X is trans, the number of enantiomers possible for X is 4

(D)   If the stereochemistry about the double bond in X is cis, the number of enantiomers possible for X is 2

Answer: (A, D)

SECTION-III

Comprehension Type

This section contains 2 groups of questions. Each group has 3 multiple choice question based on a paragraph. Each question has 4 choices (A), (B), (C) and (D) for its answer, out of which ONLY ONE is correct.

Paragraph for Question Nos. 13 to 15

p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue. Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate (II) leads to the formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent. Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a brown coloration due to the formation of Z.

13. The compound X is

(A)   NaNO3

(B)   NaCl

(C)   Na2SO4

(D)   Na2S

Answer: (D)

14. The compound Y is

(A)   MgCl2

(B)   FeCl2

(C)   FeCl3

(D)   ZnCl2

Answer: (C)

15. The compound Z is

(A)   Mg2[Fe(CN)6]

(B)   Fe[e(CN)6]

(C)   Fe4[Fe(CN)6]3

(D)   K2Zn3[Fe(CN)6]2

Answer: (B)

Paragraph for Question Nos. 16 to 18

A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S.

16. The structure of the carbonyl compound P is

(A)   

(B)  

(C)   

(D)   

Answer: (B)

17. The structure of the products Q and R, respectively, are

(A)   

(B)   

(C)  

(D)   

Answer: (A)

18. The structure of the product S is

(A)   

(B)   

(C)  

(D)   

Answer: (B)

SECTION – IV

Matrix – Match Type

This section contains 2 questions. Each question contains statements given in two columns, which have to be matched. The statements in Column I are labelled A, B, C and D, while the statements in Column II are labelled p, q, r, s and t. Any given statement in Column I can have correct matching with ONE OR MORE statement(s) in Column II. The appropriate bubbles corresponding to the answers to these questions have to be darkened as illustrated in the following example:

If the correct matches are A – p, s and t; B – q and r; C – p and q; and D – s and t; then choose the correct answer.

19. Match each of the diatomic molecules in Column I with its property/properties in Column II.

(A)   (A – s, q, r) ;  (B – p, r) ; (C – s, t) ; (D – s, p, t)

(B)   (A – q, s, p) ;  (B – r, q) ; (C – s, q) ; (D – r, t, p)

(C)   (A – s, p, q) ;  (B – r, q) ; (C – s, p) ; (D – q, s, t)

(D)   (A – p, r, t) ;  (B – s, t) ; (C – p, q) ; (D – p, q, s)

Answer: (D)

20. Match each of the compounds in Column I with its characteristic reaction(s) in Column II.

(A)   (A – p, q, s, t) ; (B – s, t) (C – p) (D – r)

(B)   (A – r, p, t, r) ; (B – p, q) (C – s) (D – t)

(C)   (A – s, t, r, q) ; (B – s, r) (C – t) (D – q)

(D)   (A – q, s, p, r) ; (B – r, p) (C – q) (D – s)

Answer: (A)

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